For a d 4 metal ion in an octahedral field, the correct electronic configuration is :

For a

d^{4}

metal ion in an octahedral field, the correct electronic configuration is :

$t_{2_{g}}^{3} e_{g}^{1}$ when $∆_{O} < P$
$t_{2_{g}}^{3} e_{g}^{1}$ when $∆_{O} > P$
$t_{2_{g}}^{4} e_{g}^{0}$ when $∆_{O} < P$
$e_{g}^{2} t_{2_{g}}^{2}$ when $∆_{O} < P$

Solution

For

d^{4}

configuration if

Δ_{0} < P

the electronic configuration is

{t_{2 g}}^{3}, e_{g}^{1}

.

Asked in: JEE Main 2020 (06 Sep Shift 2)

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