For a common-emitter amplifier, the voltage gain is 40 . Its input and output impedances are $100 \Omega$…

For a common-emitter amplifier, the voltage gain is 40 . Its input and output impedances are $100 \Omega$ and $400 \Omega$, respectively. The power gain of the $\mathrm{CE}$ amplifier will be
  1. 450
  2. 400
  3. 300
  4. 500

Solution

Power gain $=($ voltage gain $) \times($ current gain $)$ $\begin{aligned} & \text { Current gain }=\frac{\text { output current }}{\text { Input current }}=\frac{\frac{\mathrm{V}_0}{\mathrm{z}_0}}{\frac{\mathrm{V}_{\mathrm{i}}}{\mathrm{z}_{\mathrm{i}}}} \\ & =\frac{\mathrm{V}_0}{\mathrm{~V}_{\mathrm{i}}} \cdot \frac{\mathrm{z}_{\mathrm{i}}}{\mathrm{z}_0}=\frac{40 \times 100}{400}=10 \end{aligned}$ Power gain $=40 \times 10=400$

Asked in: MHT CET 2021 (22 Sep Shift 2)

Practice more Semiconductors questions on Aicharya