For a cell involving one electron E c e l l ⊝ = 0.59 V at 298 K , the equilibrium constant for the cell…

For a cell involving one electron Ecell⊝=0.59 V at 298 K, the equilibrium constant for the cell reaction is:
Given that 2.303 RTF=0.059 V at T=298 K 
  1. 1.0×102
  2. 1.0×105
  3. 1.0×1010
  4. 1.0×1030

Solution

Eo=0.59 V
ΔGo=-nFEo; Since n=1
ΔGo=-RT ln K
-1×F×0.59=-RT×2.303 log K
0.59=2.303 RTFlog K
0.59=0.059 log K
10=log K
K=1010

Asked in: NEET 2019 (All India)

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