For a CE transistor amplifier, the current amplification factor is 59 and the emitter current is $6.6 \mathrm{~mA}$. Then the base current is

Question

Aicharya · Accepted Answer

$E$ mitter current, $\mathrm{I}_{\mathrm{E}}=6.6 \mathrm{~mA}$ Current amplification, $\beta=59$ $\begin{aligned} & \mathrm{I}_{\mathrm{C}}=\beta \mathrm{I}_{\mathrm{B}}=\alpha \mathrm{I}_{\mathrm{E}} \ & \beta \mathrm{I}_{\mathrm{B}}=\frac{\beta}{1+\beta} \mathrm{I}_{\mathrm{E}} \ & \mathrm{I}_\beta=\frac{1}{1+\beta} \mathrm{I}_{\mathrm{E}}=\frac{1}{1+59} 	imes 6.6=0.11 \mathrm{~mA}\end{aligned}$

For a CE transistor amplifier, the current amplification factor is 59 and the emitter current is $6.6…

Solution