Following figure shows two processes A and B   for a gas. If ∆ Q A and ∆ Q B are the amount…

Following figure shows two processes A and B  for a gas. If QA and QB are the amount of heat absorbed by the system in two cases, and UA and UB are changes in internal energies, respectively, then:
  1. QA< QB; UA< UB
  2. QA= QB; UA= UB
  3. QA> QB; UA= UB
  4. QA> QB; UA> UB

Solution

 UA=UB as change in internal energy depends on initial and final state and not the path.
By comparing area under the curve,
WA>WB
From Q=U+W
We can say, QPA>QPB

Asked in: JEE Main 2019 (09 Apr Shift 1)

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