Flux coming out from a positive charge of $8 \mathrm{C}$, placed in a medium of dielectric constant 4 is
Flux coming out from a positive charge of $8 \mathrm{C}$, placed in a medium of dielectric constant 4 is
- $\frac{1}{2 \varepsilon_0}$
- $\frac{2}{\varepsilon_0}$
- $8 \varepsilon_0$
- $32 \varepsilon_0$
Solution
Charge enclosed, $q=8 \mathrm{C}$
Electric flux, $\phi=\frac{q}{\varepsilon_m}$
$
\varepsilon_m=K \varepsilon_0
$
Dielectric constant, $K=4$
$
\phi=\frac{8}{4 \varepsilon_0} \Rightarrow \phi=\frac{2}{\varepsilon_0}
$
Asked in: AP EAMCET 2018 (24 Apr Shift 1)
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