Fixed mass of an ideal gas contained in a $24.63$ L sealed rigid vessel at 1 atm is heated from $-73^{\circ}…
- $1231.5 \mathrm{~J}$
- $1281.5 \mathrm{~J}$
- $781.5 \mathrm{~J}$
- 0
Solution
$\Rightarrow \mathrm{P}_{2}=1 \times \frac{300}{200}=\frac{3}{2}$
and $\mathrm{V}_{1}=24.63 \mathrm{~L}$
for single phase
$\because \quad \mathrm{dG}=\mathrm{Vdp}-\mathrm{SdT}$
$\Delta \mathrm{G}=\mathrm{V} \Delta \mathrm{P}-\int\left(2+10^{-2} \mathrm{~T}ight) \mathrm{dT}$
$=1231.5-200-\left(\frac{10^{-2} \times 50,000}{2}ight)$
$=781.5 \mathrm{~J}$
Asked in: JEE-TOPICTESTS-CHEMISTRY