Five numbers x 1 , x 2 , x 3 , x 4 , x 5 are randomly selected from the numbers 1 , 2 , 3 , … … …

Five numbers x1,x2,x3,x4,x5 are randomly selected from the numbers1,2,3,,18  and are arranged in the increasing order x1<x2<x1<x4<x2. The probability that x2=7 and x4=11 is
  1. 1136
  2. 168
  3. 768
  4. 568

Solution

We know x1<7<x3<11<x5

x11,2,3,4,5,6

x38,9,10

x512,13,14,15,16,17,18

Required probability P=C16×C13×C17C518=168

Asked in: JEE Main 2022 (27 Jun Shift 1)

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