Find the value of $\left(\dfrac{1}{2}\right)^{-1} + \left(\dfrac{1}{3}\right)^{-1} +…

Find the value of $\left(\dfrac{1}{2}\right)^{-1} + \left(\dfrac{1}{3}\right)^{-1} + \left(\dfrac{1}{4}\right)^{-1}$.
  1. $9$
  2. $\dfrac{13}{12}$
  3. $\dfrac{1}{9}$
  4. $24$

Solution

Reciprocals of $\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}$ are $2, 3, 4$. Sum $= 2 + 3 + 4 = 9$.

Asked in: NSO

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