Find the third member of the Pythagorean triple $(6, 8, ?)$.

Find the third member of the Pythagorean triple $(6, 8, ?)$.
  1. $10$
  2. $12$
  3. $14$
  4. $9$

Solution

$6^{2} + 8^{2} = 36 + 64 = 100 = 10^{2}$. (This is $2 \times$ the triple $(3, 4, 5)$.)

Asked in: NSO

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