Find the resistance of a cube of edge $60 \mathrm{~cm}$, made of a material of specific resistance $60…
Find the resistance of a cube of edge $60 \mathrm{~cm}$, made of a material of specific resistance $60 \times 10^{-8} \Omega \mathrm{m}$.
- $2.5 \times 10^{-5} \Omega$
- $10^{-8} \Omega$
- $10^{-6} \Omega$
- $5 \times 10^{-4} \Omega$
Solution
Given, side of cube, $l=60 \mathrm{~cm}$
$
=60 \times 10^{-2} \mathrm{~m}
$
Resistivity, $\rho=60 \times 10^{-8} \Omega-\mathrm{m}$
$\because$ Resistance, $R=\frac{\rho l}{A}$
$
\begin{aligned}
\therefore \quad & =60 \times 10^{-8} \times \frac{60 \times 10^{-2}}{\left(60 \times 10^{-2}\right)^2} \\
& =10^{-6} \Omega
\end{aligned}
$
Asked in: AP EAMCET 2021 (23 Aug Shift 1)
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