Find the rate law for the reaction, $\mathrm{CHCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} \rightarrow…

Find the rate law for the reaction, $\mathrm{CHCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} \rightarrow \mathrm{CCl}_{4(\mathrm{~g})}+\mathrm{HCl}_{(\mathrm{g})}$ if order of reaction with respect to $\mathrm{CHCl}_{\mathrm{a}(\mathrm{g})}$ is one and $\frac{1}{2}$ with $\mathrm{Cl}_{2(\mathrm{~g})}$.
  1. Rate $=\mathrm{k}\left[\mathrm{CHCl}_3\right]\left[\mathrm{Cl}_2\right]^{1 / 2}$
  2. Rate $=\mathrm{k}\left[\mathrm{CHCl}_3\right]^2\left[\mathrm{Cl}_2\right]^{1 / 2}$
  3. Rate $=\mathrm{k}\left[\mathrm{CHCl}_3\right]^{3 / 2}\left[\mathrm{Cl}_2\right]$
  4. Rate $=\mathrm{k}\left[\mathrm{CHCl}_3\right]^{1 / 2}\left[\mathrm{Cl}_2\right]$

Solution

For typical rate equation of form $\begin{aligned} & \mathrm{r}=\mathrm{k}[\mathrm{~A}]^{\mathrm{x}}[\mathrm{~B}]^{\mathrm{y}} \\ & \Rightarrow \text { Rate }=\mathrm{k}\left[\mathrm{CHCl}_3\right]\left[\mathrm{Cl}_2\right]^{1 / 2} \end{aligned}$

Asked in: MHT CET 2023 (14 May Shift 1)

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