Find the radius, of metal atom in bcc unit cell having edge length $450 \mathrm{pm}$.

Find the radius, of metal atom in bcc unit cell having edge length $450 \mathrm{pm}$.
  1. $225.04 \mathrm{pm}$
  2. $194.85 \mathrm{pm}$
  3. $159.08 \mathrm{pm}$
  4. $99.05 \mathrm{pm}$

Solution

For bcc unit cell, $4 \mathrm{r}=\sqrt{3} \mathrm{a}$ $\therefore \quad \mathrm{r}=\frac{\sqrt{3} \mathrm{a}}{4}=\frac{1.732 \times 450}{4}=194.85 \mathrm{pm}$

Asked in: MHT CET 2023 (13 May Shift 2)

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