Find the oxidation potential of a hydrogen electrode at $p H=10$ and $p H_{2}=1$.

Find the oxidation potential of a hydrogen electrode at $p H=10$ and $p H_{2}=1$.
  1. $0.059 \mathrm{~V}$
  2. $0.59 \mathrm{~V}$
  3. $0.00 \mathrm{~V}$
  4. $0.51 \mathrm{~V}$

Solution

$E_{O P}=E_{O P}^{\circ}-\frac{0.059}{1} \log \frac{\left[H^{+}ight]}{P_{H_{2}}}$
$\therefore\left[H^{+}ight]=10^{-10} ; P_{H_{2}}=1$ atm $; E_{O P}=0.59 V$. ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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