Find the number of hydrogen atoms present in $6.0 \mathrm{~g}$ of

Find the number of hydrogen atoms present in $6.0 \mathrm{~g}$ of
  1. $2.4 \times 10^{23}$
  2. $4.06 \times 10^{23}$
  3. $2.16 \times 10^{23}$
  4. $3.01 \times 10^{23}$

Solution

Moles of urea $=6.0 / 60=0.1$ Therefore moles of $\mathrm{H}$-atoms $=0.1 \times 4=0.4$ moles Or $0.4 \times 6.02 \times 10^{23}=2.4 \times 10^{23}$

Asked in: MHT CET 2022 (11 Aug Shift 1)

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