Find the minimum height of the obstacle so that the sphere. can stay in equilibrium.
Find the minimum height of the obstacle so that the sphere. can stay in equilibrium.
\(\frac{R}{1+\cos \theta}\)
\(\frac{R}{1+\sin \theta}\)
\(R(1-\sin \theta)\)
\(R(1-\cos \theta)\)
Solution
The sphere is on the verge of toppling when a line of action of weight passes through the edge. The equilibrium is because of the line of action of weight and the normal reaction provided by the edge.
\(\cos \theta=\frac{(\mathrm{R}-\mathrm{h})}{\mathrm{R}}\)
or \(\mathrm{h}=\mathrm{R}-\mathrm{R} \cos \theta\)
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Asked in: JEE Mains - Rotational Motion - Chapter Test
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