Find the gravitational force between two stones, each of mass $2 \mathrm{~kg}$ and separated by a distance…

Find the gravitational force between two stones, each of mass $2 \mathrm{~kg}$ and separated by a distance $1 \mathrm{~m}$ in vacuum.
  1. 0
  2. $6.675 \times 10^{-5} \mathrm{~N}$
  3. $6.675 \times 10^{-11} \mathrm{~N}$
  4. $2.67 \times 10^{-10} \mathrm{~N}$

Solution

Given, masses of two stones, $m=2 \mathrm{~kg}$ Separation, $d=1 \mathrm{~m}$ Since, gravitational force, $F=\frac{G m^2}{d^2}$ where, $G=6.67 \times 10^{11} \mathrm{~N}-\mathrm{m}^2 \mathrm{~kg}^{-2}$ $\therefore \quad F=\frac{6.67 \times 10^{-11} \times 2^2}{1^2}=2.67 \times 10^{-10} \mathrm{~N}$

Asked in: AP EAMCET 2021 (23 Aug Shift 1)

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