Find the equivalent weight of $\mathrm{MnO}_4^{-}$for acid medium reactions. (Atomic weight of…

Find the equivalent weight of $\mathrm{MnO}_4^{-}$for acid medium reactions. (Atomic weight of $\mathrm{Mn}=55$, Atomic weight of $\mathrm{O}=16$ )
  1. 118.93
  2. 23.78
  3. 64.00
  4. 54.93

Solution

In acidic medium $\mathrm{Mn}^{7+} \longrightarrow \mathrm{Mn}^{2+}$ Therefore, $n$ factor $(n)=5$ $\text {Equivalent weight }=\frac{\text { Weight } \mathrm{MnO}_4^{-}}{n \text { - factor }}=\frac{119}{5}=23.8$ Hence, the correct option is (2).

Asked in: AP EAMCET 2020 (22 Sep Shift 2)

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