
Find the equivalent resistance between two ends of the following circuit

- $\frac{r}{9}$
- $\frac{\mathrm{r}}{3}$
- r
- $\frac{\mathrm{r}}{6}$
Solution

All are in parallel
$\mathrm{R}_{\mathrm{eq}}=\frac{\mathrm{r} / 3}{3}=\mathrm{r} / 9$
Asked in: JEE Main 2025 (28 Jan Shift 1)