Find the equivalent resistance between point A and B

Find the equivalent resistance between point $A$ and $B$

$65 Ω$
$20 Ω$
$5 Ω$
$2 Ω$

Solution

Therefore, $R_{A B} = \frac{(R_{A S} + 5) \times 10}{(R_{A S} + 5) + 10} = \frac{(5 + 5) \times 10}{(5 + 5) + 10} = 5 Ω$

Asked in: JEE Main 2022 (26 Jun Shift 2)

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