Find the equation of pair of straight lines that bisect the angles between the lines represented by \(a…
Find the equation of pair of straight lines that bisect the angles between the lines represented by \(a x^2+2 h x y+b y^2=0\).
\(\frac{x^2+y^2}{a+b}=\frac{x y}{h}\)
\(\frac{x^2+y^2}{a-b}=\frac{x y}{h}\)
\(\frac{x^2+y^2}{a-b}=\frac{h}{x y}\)
\(\frac{x^2-y^2}{a-b}=\frac{x y}{h}\)
Solution
The equation of pair of straight lines that bisect the angles between the lines represented by \(\begin{aligned} a x^2+2 h x y+b y^2 & =0 \\ \text { is } \frac{x^2-y^2}{a-b} & =\frac{x y}{h}\end{aligned}\)
Hence, option (d) is correct.