Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q . The distance of the point P from the centre of the rod is a = 3 2 L

Question

Aicharya · Accepted Answer

E = k &#955; a sin &#952; 1 + sin &#952; 2 E = 1 4 &#960; &#949; 0 &#215; Q L &#215; 1 3 &#160; L 2 &#215; 2 sin &#952; tan &#952; = L / 2 3 &#160; L 2 = 1 3 sin &#952; = 1 2 E = 1 4 &#960; &#949; 0 &#215; 2 Q 3 &#160; L 2 &#215; 2 &#215; 1 2 E = Q 2 3 &#960; &#949; 0 &#160; L 2

Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged…

Solution