Find the domain of the real valued function \(f(x)=\left([x]^2-[x]-2\right)^{-1 / 2}\), where \([\cdot]\) is…

Find the domain of the real valued function \(f(x)=\left([x]^2-[x]-2\right)^{-1 / 2}\), where \([\cdot]\) is the greatest integer function.
  1. \(R-(-1,3]\)
  2. \(R-[-1,3)\)
  3. \(R-(-1,3)\)
  4. \(R-[-1,3]\)

Solution

Let \(y=f(x)=\left([x]^2-[x]-2\right)^{-1 / 2}\) \(\Rightarrow \quad y^2=\frac{1}{\sqrt{[x]^2-[x]-2}}\) For real valued $\begin{aligned} & {x^2-x-2 > 0} \\ & \Rightarrow \quad{(x-2)(x+1) > 0} \\ & {x \in \mathbb{R}-(-1,2)} \\ \end{aligned}$ So, $x \in \mathbb{R}-(-1,3]$

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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