Find the degree of the differential equation \(y_3^{2 / 3}+2+3 y_2+y_1=0\).

Find the degree of the differential equation \(y_3^{2 / 3}+2+3 y_2+y_1=0\).
  1. 4
  2. 2
  3. 3
  4. 1

Solution

Given differential equation \(\begin{aligned} & & y_3^{2 / 3}+2+3 y_2+y_1=0 \\ \Rightarrow & & y_3^2=\left(-2-3 y_2-y_1\right)^3 \end{aligned}\) having degree 2 Hence, option (b) is correct.

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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