Find the concentration of sodium acetate when added to 0.1 M solution of acetic acid to form a buffer…
- 0.1 M
- 0.01 M
- 1.0 M
- 10.0 M
Solution
The Henderson-Hasselbalch equation provides the relationship between pH and buffer component concentrations:
$\mathrm{pH} = \mathrm{pK_a} + \log \frac{[\mathrm{CH_3COONa}]}{[\mathrm{CH_3COOH}]}$
Substituting the given values $\mathrm{pH} = 5.5$, $\mathrm{pK_a} = 4.5$, and $[\mathrm{CH_3COOH}] = 0.1\,\mathrm{M}$ yields:
$5.5 = 4.5 + \log \frac{[\mathrm{CH_3COONa}]}{0.1}$
Simplifying gives:
$1.0 = \log \frac{[\mathrm{CH_3COONa}]}{0.1}$
Taking the antilogarithm of both sides produces:
$10^{1.0} = \frac{[\mathrm{CH_3COONa}]}{0.1}$
Solving for the unknown concentration:
$[\mathrm{CH_3COONa}] = 10 \times 0.1 = 1.0\,\mathrm{M}$
Final answer: $1.0\,\mathrm{M}$
Asked in: MHT CET 2025 (05 May Shift 2)