Find the centripetal force acting on a coin weighing \(0.1 \mathrm{~kg}\) placed \(0.1 \mathrm{~m}\) from…

Find the centripetal force acting on a coin weighing \(0.1 \mathrm{~kg}\) placed \(0.1 \mathrm{~m}\) from the centre on a gramophone disc rotating at \(600 \mathrm{rpm}\).
  1. \(4 \pi^2 \mathrm{~N}\)
  2. \(40 \pi^2 \mathrm{~N}\)
  3. \(\frac{\pi^2}{4} \mathrm{~N}\)
  4. \(\frac{4}{\pi^2} \mathrm{~N}\)

Solution

Weight of coin, \(m=0.1 \mathrm{~kg}\) \(r=0.1 \mathrm{~m}\) Angular frequency, \(f=600 \mathrm{rpm}=\frac{600}{60} \mathrm{rps}=10 \mathrm{rps}=10 \mathrm{~Hz}\) \(\therefore\) Angular velocity, \(\omega=2 \pi f=2 \pi \times 10=20 \pi \mathrm{rad} / \mathrm{s}\) \(\therefore\) Centripetal force, \(\begin{aligned} F & =m r \omega^2=0.1 \times 0.1 \times(20 \pi)^2 \\ & =0.01 \times 400 \pi^2=4 \pi^2 \mathrm{~N} \end{aligned}\)

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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