Find the Binding energy per nucleon for Sn 50 120 . Mass of proton m p = 1 . 00783   U , mass of…

Find the Binding energy per nucleon for Sn50120. Mass of proton mp=1.00783 U, mass of neutron mn=1.00867 U and mass of tin nucleus msn=119.902199 U. (take 1U = 931 MeV)
  1. 7.5MeV
  2. 9.0MeV
  3.  8.0MeV
  4. 8.5MeV

Solution

Binding energy =(ΔM)C2=(AM)931

put the value of ∆M 

BE=8.5MeV 

Asked in: JEE Main 2020 (04 Sep Shift 2)

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