Find the area of a triangle with base $14$ cm and height $9$ cm.
Find the area of a triangle with base $14$ cm and height $9$ cm.
- $126 \text{ cm}^{2}$
- $63 \text{ cm}^{2}$
- $23 \text{ cm}^{2}$
- $252 \text{ cm}^{2}$
Solution
Area $= \dfrac{1}{2}\times b \times h = \dfrac{1}{2}\times 14 \times 9 = 63 \text{ cm}^{2}$.
Asked in: IMO
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