Find the amount of solute in solution obtained by dissolving it in $2.5 \mathrm{dm}^3$ water that generates…

Find the amount of solute in solution obtained by dissolving it in $2.5 \mathrm{dm}^3$ water that generates osmotic pressure $0.245 \mathrm{~atm}$. at $300 \mathrm{~K}$ ? (Molar mass of solute $=58 \mathrm{~g} \mathrm{~mol}^{-1} \mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )
  1. 1.75 gram
  2. 1.0 gram
  3. 0.72 gram
  4. 1.44 gram

Solution

$\begin{aligned} & \pi=C R T \\ & 0.245=\frac{W}{58} \times \frac{1}{2.5} \times 0.0821 \times 300 \\ & W=1.44 \mathrm{~g}\end{aligned}$

Asked in: MHT CET 2022 (10 Aug Shift 1)

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