Find $y - x$ where $x$ is the largest integer with $2^{x} < 10^{6}$ and $y$ is the smallest integer with…
Find $y - x$ where $x$ is the largest integer with $2^{x} < 10^{6}$ and $y$ is the smallest integer with $10^{6} < 2^{y}$.
- $0$
- $1$
- $2$
- $19$
Solution
$2^{19} = 524{,}288 < 10^{6}$ and $2^{20} = 1{,}048{,}576 > 10^{6}$. So $x = 19$, $y = 20$, hence $y - x = 1$.
Asked in: IMO
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