Find $(3 \times 10^{-4})^{2}$.

Find $(3 \times 10^{-4})^{2}$.
  1. $9 \times 10^{-8}$
  2. $9 \times 10^{-16}$
  3. $6 \times 10^{-8}$
  4. $9 \times 10^{-2}$

Solution

$(3)^{2} \times (10^{-4})^{2} = 9 \times 10^{-8}$.

Asked in: IMO

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