Find \(\alpha^4+\beta^4\) if \(\alpha, \beta\) are the roots of equation \(x^2+x+1=0\).

Find \(\alpha^4+\beta^4\) if \(\alpha, \beta\) are the roots of equation \(x^2+x+1=0\).
  1. \(\frac{1}{\alpha \beta}\)
  2. \(\frac{2}{\alpha \beta}\)
  3. \(\alpha \beta\)
  4. \(-\alpha \beta\)

Solution

The roots of the equation \(x^2+x+1=0\) are \(\alpha\) and \(\beta\) and \(\alpha^3=\beta^3=1\) and \(\alpha+\beta+1=0\) \(\{\because \alpha, \beta\) are non-real cube roots of unity \(\}\) \(\begin{aligned} \therefore \quad & \alpha^4+\beta^4=\alpha+\beta \\ & =-1=-\alpha \beta \quad \quad\{\because \text { product of roots } \alpha \beta=1\} \end{aligned}\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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