Find \(\alpha^4+\beta^4\) if \(\alpha, \beta\) are the roots of equation \(x^2+x+1=0\).
Find \(\alpha^4+\beta^4\) if \(\alpha, \beta\) are the roots of equation \(x^2+x+1=0\).
\(\frac{1}{\alpha \beta}\)
\(\frac{2}{\alpha \beta}\)
\(\alpha \beta\)
\(-\alpha \beta\)
Solution
The roots of the equation \(x^2+x+1=0\) are \(\alpha\) and \(\beta\) and \(\alpha^3=\beta^3=1\) and \(\alpha+\beta+1=0\)
\(\{\because \alpha, \beta\) are non-real cube roots of unity \(\}\)
\(\begin{aligned}
\therefore \quad & \alpha^4+\beta^4=\alpha+\beta \\
& =-1=-\alpha \beta \quad \quad\{\because \text { product of roots } \alpha \beta=1\}
\end{aligned}\)