Figure shows three capacitors connected to a \(6 \mathrm{~V}\) power supply. What is the charge on the \(2…
Figure shows three capacitors connected to a \(6 \mathrm{~V}\) power supply. What is the charge on the \(2 \mu \mathrm{F}\) capacitor?
\(1 \mu \mathrm{C}\)
\(2 \mu \mathrm{C}\)
\(3 \mu \mathrm{C}\)
\(4 \mu \mathrm{C}\)
Solution
- Given the circuit diagram shows that 3 capacitors are connected to a 6 \(V\) power supply. The capacitor of capacitance 2 micro \(F\) and 3 micro \(F\) are in parallel and connected in series with 1 micro \(F\). Therefore 1 micro F is in series with 3 micro F capacitor. Now there is a potential difference of 6 V across this series combination. Now the parallel add this combination of 2 and 3 micro \(F=5\) micro \(F\) is 1 V.\r\n- Therefore the charge on 2 micro F capacitor \(=2 \mu \mathrm{F} \times \mathrm{1 V}=\mathrm{2} \mu \mathrm{C}\)
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