Figure shows five capacitors connected across a $12 \mathrm{~V}$ power supply. What is the charge on the $2 \mu \mathrm{F}$ capacitor?

Question

Aicharya · Accepted Answer

Capacitors $1 \mu \mathrm{F}, 2 \mu \mathrm{F}$ and $3 \mu \mathrm{F}$ are in parallel, their total capacitance is $6 \mu \mathrm{F}$. Thus, we have three capacitors in series each of capacitance $6 \mu \mathrm{F}$ across the $12 \mathrm{~V}$ power supply So, the potential drop across each is $12 / 3=4 \mathrm{~V}$. This is also the potential across $1 \mu \mathrm{F}$ capacitor and $2 \mu \mathrm{F}$ capacitor and $3 \mu \mathrm{F}$ capacitor, because they are in parallel. Therefore, charge on $2 \mu \mathrm{F}$ capacitor $=2 \mu \mathrm{F} \times 4 \mathrm{~V}=8 \mu \mathrm{C}$. Hence the correct choice is (b).

Figure shows five capacitors connected across a \(12 \mathrm{~V}\) power supply. What is the charge on the…

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