Figure shows charge ( q ) versus voltage ( V ) graph for series and parallel combination of two given…

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are:
  1. 60 μF  and  40 μF
  2. 50 μF  and  30 μF
  3. 20 μF  and  30 μF
  4. 40 μF  and  10 μF

Solution

Q=CV
The slope of graph will give the equivalent capacitance of the combination.
From graph A: C1+C2=50010=50 …(i)
From graph B: C1C2C1+C2=8010=8 …(ii)
From equation (i) & (ii)
C1C2=400 …(iii)
C1+400C1=50 C12-50C1+400=0
C1=50±2500-16002=50±302
=10μF,  40μF

Asked in: JEE Main 2019 (10 Apr Shift 1)

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