Figure shows a rod A B , which is bent in a 120 ° circular arc of radius R . A charge   ( - Q ) is…

1. $\frac{3\sqrt{3}Q}{8{\pi }^2{\epsilon }_0{R}^2} \hat{\mathrm{i}}$
2. $\frac{3\sqrt{3Q}}{8\pi {\epsilon }_0{R}^2} \hat{\mathrm{i}}$
3. $\frac{-3\sqrt{3}Q}{8{\pi }^2{\epsilon }_0{R}^2} \hat{\mathrm{i}}$
4. $\frac{3\sqrt{3Q}}{16{\pi }^2{\epsilon }_0{R}^2} \hat{\mathrm{i}}$

Solution

Asked in: JEE Main 2021 (27 Aug Shift 2)

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