Figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB,…

Figure below shows two paths that may be taken by a gas to go from a state A to a state C.

In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:
  1. 380 J
  2. 500 J
  3. 460 J
  4. 300 J

Solution

In cyclic process ABCA,
ΔUcyclic=0
Qcyclic=W
QAB+QBC+QCA=  Closed loop area
400+100+QCA=12×2×10-3×4×104
500-QAC=40
QAC=460 J *

Asked in: NEET 2015 (Phase 1)

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