Father's age is twice his son's age. Sum of ages is $48$. Father's age is

Father's age is twice his son's age. Sum of ages is $48$. Father's age is
  1. $32$
  2. $16$
  3. $24$
  4. $30$

Solution

Father $= 2x$, son $= x$. $3x = 48 \Rightarrow x = 16$. Father $= 32$.

Asked in: MH-SSC-9

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