Factorise $x^{3} - 8$.

Factorise $x^{3} - 8$.
  1. $(x-2)(x^{2} + 2x + 4)$
  2. $(x+2)(x^{2} - 2x + 4)$
  3. $(x-2)^{3}$
  4. $(x-2)(x+2)(x^{2}+4)$

Solution

$a^{3} - b^{3} = (a-b)(a^{2} + ab + b^{2})$.

Asked in: MH-SSC-9

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