Factorise $x^{2} - 4x - 21$.
Factorise $x^{2} - 4x - 21$.
- $(x - 7)(x + 3)$
- $(x + 7)(x - 3)$
- $(x - 21)(x + 1)$
- $(x - 7)(x - 3)$
Solution
Need $a+b=-4, ab=-21$: $a=-7, b=3$. So $(x-7)(x+3)$.
Asked in: IMO
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