Factorise $x^{2} - 16$.

Factorise $x^{2} - 16$.
  1. $(x - 4)(x + 4)$
  2. $(x - 4)^{2}$
  3. $(x + 4)^{2}$
  4. $(x - 8)(x + 2)$

Solution

$x^{2}-16 = x^{2} - 4^{2} = (x-4)(x+4)$.

Asked in: IMO

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