Factorise $a^{2} + bc + ab + ac$.
Factorise $a^{2} + bc + ab + ac$.
- $(a+b)(a+c)$
- $(a-b)(a+c)$
- $(a+b)(a-c)$
- $(a+bc)(a+1)$
Solution
Group as $(a^{2}+ab)+(ac+bc) = a(a+b)+c(a+b) = (a+b)(a+c)$.
Asked in: IMO
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