Factorise $9x(x-3) - 6(x-3)$.
Factorise $9x(x-3) - 6(x-3)$.
- $3(x-3)(3x-2)$
- $3(x-3)(3x+2)$
- $(x-3)(9x-6)$
- $9(x-3)(x-2)$
Solution
Take $3(x-3)$ common: $3(x-3)(3x-2)$. (Numerical GCD of 9 and 6 is 3, and $(x-3)$ is the binomial GCD.)
Asked in: IMO
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