Factorise $5(2x-3)^{2} - 10(2x-3)$.
Factorise $5(2x-3)^{2} - 10(2x-3)$.
- $5(2x-3)(2x-5)$
- $5(2x-3)(2x-1)$
- $10(2x-3)(x-1)$
- $5(2x-3)^{2}(2x-3)$
Solution
Take $5(2x-3)$ common: $5(2x-3)\big[(2x-3)-2\big] = 5(2x-3)(2x-5)$.
Asked in: IMO
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