Factorise $49x^{2} - 28xy + 4y^{2}$.
Factorise $49x^{2} - 28xy + 4y^{2}$.
- $(7x - 2y)^{2}$
- $(7x + 2y)^{2}$
- $(7x - 2y)(7x + 2y)$
- $(7x - 4y)(7x - y)$
Solution
$49x^{2}-28xy+4y^{2} = (7x)^{2} - 2 \cdot 7x \cdot 2y + (2y)^{2} = (7x-2y)^{2}$.
Asked in: IMO
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