Factorise $3x^{2} - 10x + 8$.

Factorise $3x^{2} - 10x + 8$.
  1. $(3x - 4)(x - 2)$
  2. $(3x + 4)(x - 2)$
  3. $(3x - 2)(x - 4)$
  4. $(x - 8)(3x - 1)$

Solution

Product $=24$, sum $=-10$: $-6,-4$. $3x^{2}-6x-4x+8 = 3x(x-2)-4(x-2) = (3x-4)(x-2)$.

Asked in: IMO

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