Exterior angle at $A$ in triangle $ABC$ is $130^{\circ}$, $\angle B = 60^{\circ}$. Then $\angle C$ equals

Exterior angle at $A$ in triangle $ABC$ is $130^{\circ}$, $\angle B = 60^{\circ}$. Then $\angle C$ equals
  1. $70^{\circ}$
  2. $130^{\circ}$
  3. $60^{\circ}$
  4. $50^{\circ}$

Solution

Exterior at $A = \angle B + \angle C \Rightarrow 130 = 60 + \angle C \Rightarrow \angle C = 70^{\circ}$.

Asked in: MH-SSC-9

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