Express $\frac{d t}{d x}=\frac{t}{\left(x+t e^{-2 x / 4}\right)}$ in the form of $\frac{d x}{d t}=\phi\left(\frac{x}{t}\right)$

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Aicharya · Accepted Answer

$\frac{d t}{d x}=\frac{t}{x+t e^{\frac{-2 x}{t}}}$ On reciprocal, we get $ \frac{d x}{d t}=\frac{x+t e^{\frac{-2 x}{t}}}{t}=\left(\frac{x}{t}\right)+e^{-2\left(\frac{x}{t}\right)} $ Hence, option (1) is correct

Express $\frac{d t}{d x}=\frac{t}{\left(x+t e^{-2 x / 4}\right)}$ in the form of $\frac{d x}{d…

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