Ethanol on treatment with concentrated HI and red phosphorus forms

Ethanol on treatment with concentrated HI and red phosphorus forms
  1. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}$
  2. $\mathrm{C}_{2} \mathrm{H}_{4}$
  3. $\mathrm{C}_{2} \mathrm{H}_{6}$
  4. $\mathrm{C}_{3} \mathrm{H}_{8}$

Solution

$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{HI} / \mathrm{P}}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{H}_{2} \mathrm{O}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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