Equation of the tangent to the circle, at the point 1 ,   - 1 , whose center, is the point of intersection of the straight lines x - y = 1 and 2 x + y = 3 is:

Question

Equation of the tangent to the circle, at the point 1 , &#160; - 1 , whose center, is the point of intersection of the straight lines x - y = 1 and 2 x + y = 3 is:

Aicharya · Accepted Answer

Point of intersection of lines x - y = 1 and 2 x + y = 3 O is 4 3 , 1 3 Slope of O P = 1 3 + 1 4 3 - 1 = 4 3 1 3 = 4 Slope of tangent = - 1 4 &#8658; Equation of tangent : y + 1 = &#160; - 1 4 x - 1 &#8658; 4 y + 4 = - x + 1 &#8658; x + 4 y + 3 = 0

Equation of the tangent to the circle, at the point 1 ,   - 1 , whose center, is the point of…

Solution

Equation of the tangent to the circle, at the point 1 , &#160; - 1 , whose center, is the point of…

Solution

Equation of the tangent to the circle, at the point 1 , - 1 , whose center, is the point of…